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Re: mingw-targeted cross-compiler question


2010/12/22  <lemkemch@t-online.de>:
> On Wed, 22 Dec 2010 14:13:15 +0100, Frédéric Bron <frederic.bron@m4x.org>
> wrote:
>
>>>>> I checked the Make file, it used this flag:
>>>>> gcc -mno-cygwin -g -Wl,--add-stdcall-alias -Wl,--export-all-symbols ...
>>>>
>>>> replace gcc by gcc-3
>>>> gcc 4 is now the default on cygwin but the cross compiler is not
>>>> supported for that version.
>>>> Frédéric
>>>
>>> What do you mean by not supported? ?JonY maintains the cross
>>> compilers....
>>
>> I meant that i686-w64-mingw32-gcc exists but not i686-w32-mingw32-gcc.
>> I thought that w64 meant "built on win64" and mingw32 "run binary on
>> win32".
>> So it seems to me that with cygwin running on a 32 bit windows, it is
>> not possible to cross compile to win32. However with a 64 bit windows
>> you can produce win32 applications.
>> However, I just tried to use i686-w64-mingw32-g++ on my win32 machine
>> with a hello world program and it produces an binary that can be used
>> from windows on that win32 machine.
>> So my question to the list: what is the meaning of w64 in the name?
>
> Well, I don't know but I'd really like to know what is the replacement
> these days for
>
> gcc -mno-cygwin -mwindows x.c
>
> I tried
>
> i686-w64-mingw32-gcc -mwindows ?-m32 x.c
>
> but get
>
> x.c:35:13: error: expected '=', ',', ';', 'asm' or '__attribute__' before
> 'WinMain'
>
> and that also for all other option combinations that made sense to me.
>
> Thanks,
> Michael

Hi,

the -w64- within cross-compiler's triplet means that this compiler
uses mingw-w64 runtime headers and libraries. The architecture part of
triplet (i686|x86_64) makes the difference, if a cross-compiler
produces binaries for i686 (means 32-bit), or for x86_64  (means
64-bit) windows native.
Btw the -m32 is superflous for the i686-w64-mingw32 cross-compiler, as
it just produces 32-bit and has no 64-bit capabilities builtin.
Could you show please your x.c file, as the message you get is a
compiler error already. I would assume that you missed to include some
header, or you were defining something which cause here the harm.

Regards,
Kai


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