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RE: echo with sh.exe doesn't understand multiple parameters
- To: "Bob McGowan" <rmcgowan at veritas dot com>
- Subject: RE: echo with sh.exe doesn't understand multiple parameters
- From: "John Pollock" <jpollock at curl dot com>
- Date: Thu, 19 Oct 2000 18:43:45 -0400
- Cc: <cygwin at sourceware dot cygnus dot com>
Thanks Bob and others who responded. FWIW, sh on Linux accepts -e and -n at
the same time, which is how we managed to run into our trouble (we do
concurrent builds on Linux and Windows). But i'll be changing
our -e -n references to use -e and \c.
Thanks!
John
-----Original Message-----
From: Bob McGowan [mailto:rmcgowan@veritas.com]
Sent: Thursday, October 19, 2000 4:18 PM
To: John Pollock
Subject: Re: echo with sh.exe doesn't understand multiple parameters
These are mutually exclusive options. The -n makes echo emulate the old
Bourne shell behavior, -e the new.
echo -n test
and
echo -e 'test\c'
Are equivalent. The other backslash sequences recognized when -e is used
had no equivalent in older shells. You had to embed litteral characters,
where possible.
Hope this helps.
John Pollock wrote:
>
> With the echo command, using -n or -e alone with sh works fine:
>
> $ echo -e blah
> blah
> $ echo -n blah
> blah$
>
> but when you try to use both flags at once, sh seems to get confused:
>
> blah$ echo -n -e blah
> -e blah$
>
> Is there a workaround?
>
> John
>
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--
Bob McGowan
Staff Software Quality Engineer
VERITAS Software
rmcgowan@veritas.com
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