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RE: SNR calculations (was Re: setup.exe missing from FTP site)
On 26 May 2007 22:47, Brian Dessent wrote:
> Linda Walsh wrote:
>
>>> I prefer to express that as an SNR of -18dB :-)
>> ---
>> Could you please show your work!
>>
>> I arrived at -9dB. Work:
>> For each doubling/halving of power one adjusts by ~(+/-)3dB.
>> (note: "3" is approximation of 10*log(2) or,
>> to 7 decimal places, 3.010900)
>> so 1 unit / 2 units of signal would be -3dB,
>> 1 unit / 4 units: -6dB,
>> 1 unit / 8 units: -9dB
>>
>> From my limited understanding, -18dB would be a reduction of 6
>> factors of 2, or a 1:64 signal/noise ratio.
>
> Typically you use dB to compare the amount of power in a signal relative
> to a fixed reference; in the case of electronics a common reference is
> 1mV, or 0 dBmV. Since power in a signal is proportional to V^2, when you
> compute dBmV from a voltage level it's 20*log(v) due to the power of 2.
>
> But when you just want to use dB to represent a unitless ratio, then I
> agree with you it's simply 10*log(ratio).
>
> Brian
For purposes of humour, the larger magnitude number is always better. Hence
I counted 6dB per doubling. The fact that it was technically correct is a
mere beneficent side-effect!
cheers,
DaveK
--
Can't think of a witty .sigline today....